# Stoichiometry – Watch Video

All the Tricks and Techniques you need to **Master Stoichiometry In Chemistry**. Score high in Stoichiometry Theory, Objective and Calculations Questions.

## Requirements:

- You should possess basic Chemistry knowledge
- Posses basic mathematical skills
- Understand change of subject formular

## Who Is This Video For?

- Students Interested in Chemistry
- People who wish to understand Stoichiometry
- Students Preparing for School Examination
- Candidates preparing for Scholarships
- Jamb, Waec and Neco Candidates

## Stoichiometry Video

## Stoichiometry Topics

This Video Covers the Following Topics Among Others…

- Meaning of Stoichiometry
- Quantitative And Qualitative Analysis
- Chemical Equations
- Stoichiometric Coefficient
- Mole Ratio
- Stoichiometry Questions Format
- Law of Conservation of Mass
- How to Chemical Equations
- Stoichiometry Questions And Answers
- Mass of Carbon Present
- Percentage by Mass of Oxygen
- Limiting and Excess Reagents Calculations
- Formulars for Solving Stoichiometry
- Calculating Number of Molecules
- Calculating Volume of Resulting Gases
- More Stoichiometry Calculation Questions

## Stoichiometry Calculations

The following are Calculation Questions covered in this video among others….

A. Calculate the volume of 0.1M ammonia which could be obtained by heating 2.7g of ammonium chloride with excess sodium hydroxide and absorbing all the ammonia evolved.

B. 50cm3 of CO is mixed and sparked with 200cm3 of air containing 21% of O2. If all the volumes are measured at S.T.P. Calculate the total volume of the residual gases.

C. Determine the limiting reagent when 10g of hydrogen reacts with 18g of oxygen to form water according to the equation

2H_{2} + O_{2} → 2H_{2}O

C. What is the percentage by mass of Oxygen in Al_{2}(SO_{4})_{3}.2H_{2}O

D. How many grams of H_{2}SO_{4} are necessary for the preparation of 0.175dm^{3} of 6.00M H_{2}SO_{4}.

E. Calculate the number of molecules of carbon (IV) oxide produced when 15g of CaCO3 is treated with 200cm^{3} of 0.2 moldm^{-3} HCL. The equation for the reaction is

CaCO_{3 (s)} + 2HCL_{(aq) }→ CaCl_{2(aq}) + H20_{(l)} + CO2_{(g)}

We might live in a digital age, but students still need to use pencils. There’s tons of research about…

Copyright © 2023 The Back to School Blog. All rights reserved.